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Physics 16 Online
OpenStudy (anonymous):

Okay so i'm totally lost :/ help plz..... I will fan and metal Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Use the formulas and the energy level information below to answer the question. Needed constants: 1.00eV=1.6*10^(-19) J C= 3.0*10^(8) M/J H= 6.63*10^(-34) J*S Energy Level Values: E6:E= -0.378eV E5:E= -0.544eV E4:E= -0.850eV E3:E= -1.51eV E2:E= -3.403V

OpenStudy (anonymous):

@amistre64 @johnnybot @pinksparkles @RideBmx @prettyhutts16

OpenStudy (anonymous):

@Warriorz13

OpenStudy (anonymous):

http://www.askthephysicist.com/ask_phys_q&a_old.html

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

@Warriorz13

OpenStudy (anonymous):

do u want the EXACT formula for the calculation of the wavelength? or a better approach( a bit longer) , that is more explanatory?

OpenStudy (warriorz13):

lol i have no freaking clue srry hun lmfao

OpenStudy (warriorz13):

I'm already here

OpenStudy (anonymous):

can You type the formula and me and you work it out together ? (: @AnthonyStark

OpenStudy (anonymous):

,,im really sorry i dont know the exact formula for this specific question,,,,but u can get it using the basics,,,

OpenStudy (anonymous):

lets put the question in simple terms ;;;;;- this is what happens,,, an electron in some energy level (say 5th level) decides to fall back to a lower energy level (say 3rd) ,,and when this happens a photon having energy equal to the difference in energy levels of these , is given out |dw:1399565019491:dw|

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