Question

question below MEDAL!

Answer 1

A principal ordered 3,500 snack bars for the after-school program at school. There are 330 middle school students and 156 elementary school students. If each student eats one snack bar a day, which equation best represents d, the number of days, there will be enough snacks for the students?

Is it:
a. 3500= 330d + 156d
b. d = 3500 - (330 + 156)

Answer 2

@whpalmer4 @Hero

Answer 3

@Nurali

Answer 4

i think it is b. but i am not too sure.

Answer 5

well, how many snacks will be eaten in 1 day?

Answer 6

330+156=486?

Answer 7

is it b or not?

Answer 8

sorry i meant a?

Answer 9

@e.mccormick

Answer 10

@agent0smith

Answer 11

Well, you are given that there are 3500 snack bars.

And there are 330 middle school and 156 elem. school students.
That is a total of 486 students.

So each day, 486 students eat one snack bar.

Or 486 bars / day.

You can take this like a speed-distance-time problem.

Here the speed or the rate is = 486 bars per day
Distance/ no. of bars = 3500 bars.

Time / No. of days = \(\frac{Total ~~number~~ of ~~bars}{Rate~~ of~~ eating~~ them~~ per ~~day}\) = 3500/486

So yes, it must be 'a'.

Did you get why? :)

Answer 12

I wonder if b isn't supposed to have a division sign instead of a subtraction sign...

\[d = 3500\div (330 + 156)\]