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Mathematics 13 Online
OpenStudy (anonymous):

if x=-4 evaluate -x

OpenStudy (anonymous):

4?

OpenStudy (anonymous):

multiple each side by a negative, your answer should be 4

OpenStudy (anonymous):

thank

OpenStudy (anonymous):

| –1| + | 0.8|

OpenStudy (anonymous):

absolute value bars means everything inside is positive so basically you get 1 + 0.8... so that gives you... ? :)

OpenStudy (anonymous):

the line means absolute value right? then it's just 1+0.8=1.8

OpenStudy (anonymous):

@iheartfood sorry I gave the answer :P

OpenStudy (anonymous):

haha no worries :P

OpenStudy (anonymous):

5/20 as a percent and a decimal.

OpenStudy (anonymous):

can you find the decimal? Just do normal division

OpenStudy (anonymous):

after you get the decimal form, just multiply by a hundred to get percent

OpenStudy (anonymous):

Which number is between 1/9 and 0.2 ?

OpenStudy (anonymous):

convert the fraction to decimal form (or do the opposite, convert the decimal to fraction). Then see for yourself :)

OpenStudy (anonymous):

Evaluate x + y when x = –21.6 and y = 2.3

OpenStudy (anonymous):

just substitute the numbers in, you should get a number

OpenStudy (anonymous):

THANK YOU

OpenStudy (anonymous):

Simplify 6 – 4x – 2 + x.

OpenStudy (anonymous):

well... collect the like terms. You have 6-2 and -4x + x. Whats the answer?

OpenStudy (anonymous):

combine like terms :) so 6 - 2 = and -4x + x = ? :D

OpenStudy (anonymous):

ohh haha oops same thing @alias said

OpenStudy (anonymous):

haha, our paths crossed again :P

OpenStudy (anonymous):

4 – 3x

OpenStudy (anonymous):

haha yes @alias and @otis13 that is correct! good job :)

OpenStudy (anonymous):

Evaluate if w = –2.1 and z = 5.7. w – z – 4

OpenStudy (anonymous):

substitute those values and solve!

OpenStudy (anonymous):

it's the same problem as the last

OpenStudy (anonymous):

find the reciprocal of - b/3

OpenStudy (anonymous):

reciprocal mean opposite...

OpenStudy (anonymous):

also, you will get more help if you just start a new post for every new question you have

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