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3square root of 2x=12
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Your equation is \[3\sqrt{2x} = 12\] Divide by three on both sides to get \[\sqrt{2x} = 4\] Now square both sides to remove the square root, 2x = 16 Thus you get x = 8.
the 3 is the q number right?
are we sure 3 square root is not meant to be cube root...?
i think its the question number :P
If 3 is a question number, following the same process described in the first answer, you should be able to get x = 72. If 3 is for cube root, your answer, instead of squaring both sides, cube both sides to and then solve the equation. The answer in this case should be x = 864
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@navk ur logic and maths are flawless man, but stop givin the answers dudde... just the solutions are fine hey ;)
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