what is the slope of a line perpendicular to the line 6x + 3y = 15
the slope of a line perpendicular to a line would be the flipped opposite of the given slope. so for Example, if you were given a slope of 4/3 the slope of the perpendicular would be -3/4
how would i show work
just show your work of turning given equation into slope-intercept form equation.
then take slope (m) and turn it into -1/m
if slope is m, then the slope of line perpendicular of original line is -1/m, just like example @jigglypuff314 gave you.
i dont understand what u guys are saying :'( . i did an additive inverse
ok, well first figure out the slope of the given equation :) do you know how to do that?
i know like the formula for slope: y2-y1/x2-x1
right?
that's when you're given two points :) for when you're given an equation, you would want to get it into slope intercept form y = mx + b where m = slope so solve for y from 6x + 3y = 15
oh. so
3y= 6x + 15?
3y = -6x + 15 :) good, then divide both sides by 3 to get y alone
so y = -2x + 5
yep! :D then given y = mx + b where m=slope find the slope of y = -2x + 5
-2? :D
correct! :) now take the flipped opposite of it like I showed in the first comment
umm. idk what that means ._.
for Example, if you were given a slope of 4/3 the slope of the perpendicular would be -3/4
so. the slope is positive 2?
close ^_^ don't forget to flip it
1/2 ?
Correct!!! :D :D :D
YAY
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