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\[\sum2a_n+n=2\sum a_n+\sum n\]
one of these numbers on the right you are told, we have \[2\times 10+\sum_{n+1}^{100}n\] and the second term should be easy to compute
Am I just supposed to end up with a numerical answer?
yes
\(2\times 10=20\) is the first number do you know how to compute \[\sum_{n=1}^{100}n\]?
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It would be 5050 right? I looked it up but I'm not sure how to actually compute that without looking it up
\[\sum_{n=1}^kn=\frac{k(k+1)}{2}\] and so \[\sum_{n=1}^{100}n=\frac{(100)(101)}{2}=50\times 101\]
So it would just be 5070 then?
yes
Okay thanks :)
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yw
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