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Mathematics 19 Online
OpenStudy (anonymous):

The graph below shows a line segment XY. graph of line XY going through ordered pairs negative 2, 4 and 1, negative 5 Which of the following equations best represents the line segment XY? y = -3x + 2 y = -2x + 1 y = -3x - 2 y = -2x - 1

OpenStudy (anonymous):

OpenStudy (anonymous):

Its decreasing so im guessing it will be either b or c

OpenStudy (anonymous):

can u find the slope m = ?

OpenStudy (anonymous):

-3?

OpenStudy (anonymous):

equation for straight line y = m.x + c , m is slope, c is where the line intersects with the Y-axis

OpenStudy (anonymous):

isn't it y=mx+b?

OpenStudy (anonymous):

m= -3 is correct , what is c?

OpenStudy (anonymous):

same thing, sorry i should have used b instead

OpenStudy (anonymous):

and b is the y intercept right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

-2?

OpenStudy (anonymous):

correct :)

OpenStudy (anonymous):

so the answer is c?

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

Thank You! By any chance can you help me with another? Its the same type of question.

OpenStudy (anonymous):

sure, btw m = (y2 - y1)/(x2 - x1)

OpenStudy (anonymous):

yes that is point-slope right?

OpenStudy (anonymous):

i call it slope, not sure what ur level of maths call it

OpenStudy (anonymous):

and the question is about perpendicular lines just to let you know u up for the challenge?

OpenStudy (anonymous):

damn... me no like challenge :)

OpenStudy (anonymous):

Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. line through the points 0 comma 6 and negative 2 comma 0 with a point 6 comma 2 not on the line y = one thirdx y = -one thirdx + 4 y = 3x + 20 y = -3x - 16

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

what was the rule for slopes of 2 lines that are perpendicular ? was it m1.m2 = -1 ?

OpenStudy (anonymous):

im not sure lol

OpenStudy (anonymous):

the slope of line 1 is what? m1 = (6-0)/(0- -2) = 6/2 = 3

OpenStudy (anonymous):

3/1

OpenStudy (anonymous):

m2 = -1/3 from the rule I stated above

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

so its the exact oppisite

OpenStudy (anonymous):

{x=t2+2y=t2−4 Write both equations in terms of t²: {t2=x−2t2=y+4 Now setting them equal to each other, you have x−2=y+4y=x−6 @mathman123

OpenStudy (anonymous):

now u need to find another point for line 2 to be able to draw it, so u have 1 point which is (6,2) and its slope -1/3 can u find another point using this formula m2 = (y2-y1)/(x2-x1) by sustituting m2 = -1/3 y1 = 2 x1 = 6 ???

OpenStudy (anonymous):

so what does m1 equal

OpenStudy (anonymous):

m1 is the slope of the first line, we found it above = 3/1 = 3

OpenStudy (anonymous):

and y2

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

y2 is the y coordinate of a point on the second line hold on let me draw u a picture, ok?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

|dw:1399760452361:dw|

OpenStudy (anonymous):

is it perpendicular?

OpenStudy (anonymous):

yes sorry my drawing isnt perfect

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

so wouldn't the slope be the exact opposite?

OpenStudy (anonymous):

yes u r right in a sense it is oppsite, instead of m1 = 3 it is -1/3 i.e the negative of the reciprocal of m1

OpenStudy (anonymous):

yea that's what I meant lol sorry I should've explained *opposite* better

OpenStudy (anonymous):

m2 = (y2-y1)/(x2-x1) m2 = -1/3 , y2 = 2, x2 = 6 so -1/3 = (2-y1)/(6-x1) from the above can u find x1 and y1 ?

OpenStudy (anonymous):

uh im not the best at point slope but ill take a go at it

OpenStudy (anonymous):

|dw:1399760897759:dw|

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