The graph below shows a line segment XY. graph of line XY going through ordered pairs negative 2, 4 and 1, negative 5 Which of the following equations best represents the line segment XY? y = -3x + 2 y = -2x + 1 y = -3x - 2 y = -2x - 1
Its decreasing so im guessing it will be either b or c
can u find the slope m = ?
-3?
equation for straight line y = m.x + c , m is slope, c is where the line intersects with the Y-axis
isn't it y=mx+b?
m= -3 is correct , what is c?
same thing, sorry i should have used b instead
and b is the y intercept right?
yes
-2?
correct :)
so the answer is c?
correct
Thank You! By any chance can you help me with another? Its the same type of question.
sure, btw m = (y2 - y1)/(x2 - x1)
yes that is point-slope right?
i call it slope, not sure what ur level of maths call it
and the question is about perpendicular lines just to let you know u up for the challenge?
damn... me no like challenge :)
Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. line through the points 0 comma 6 and negative 2 comma 0 with a point 6 comma 2 not on the line y = one thirdx y = -one thirdx + 4 y = 3x + 20 y = -3x - 16
lol
what was the rule for slopes of 2 lines that are perpendicular ? was it m1.m2 = -1 ?
im not sure lol
the slope of line 1 is what? m1 = (6-0)/(0- -2) = 6/2 = 3
3/1
m2 = -1/3 from the rule I stated above
oh ok
so its the exact oppisite
{x=t2+2y=t2−4 Write both equations in terms of t²: {t2=x−2t2=y+4 Now setting them equal to each other, you have x−2=y+4y=x−6 @mathman123
now u need to find another point for line 2 to be able to draw it, so u have 1 point which is (6,2) and its slope -1/3 can u find another point using this formula m2 = (y2-y1)/(x2-x1) by sustituting m2 = -1/3 y1 = 2 x1 = 6 ???
so what does m1 equal
m1 is the slope of the first line, we found it above = 3/1 = 3
and y2
oh ok
y2 is the y coordinate of a point on the second line hold on let me draw u a picture, ok?
ok
|dw:1399760452361:dw|
is it perpendicular?
yes sorry my drawing isnt perfect
lol
so wouldn't the slope be the exact opposite?
yes u r right in a sense it is oppsite, instead of m1 = 3 it is -1/3 i.e the negative of the reciprocal of m1
yea that's what I meant lol sorry I should've explained *opposite* better
m2 = (y2-y1)/(x2-x1) m2 = -1/3 , y2 = 2, x2 = 6 so -1/3 = (2-y1)/(6-x1) from the above can u find x1 and y1 ?
uh im not the best at point slope but ill take a go at it
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