Question

Solve: 9x^2 + 3x = 0

Answer 1

factor out the x, you get x (9x + 3). From there set each equal to 0 and solve for x

Answer 2

x = 0 @jjuden Do you understand why? @jjuden

Answer 3

@Tom_Boy_Rebel you dont have to put @jjuden

Answer 4

ok

Answer 5

there are two solutions x=0 and x=-1/3

Answer 6

x = 0 or x = -1/3 do you understand why or do you need more help?

Answer 7

@mathman123 i know but how do i get them

Answer 8

I will show you how jjuden

Answer 9

stop putting jjuden please

Answer 10

use the quadratic formula to solve it
\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac}}{ 2a }\]

Answer 11

it doesnt say to use the quadratic formula i olny use that when it tells me to

Answer 12

9x^2 + 3x = 0
Factor out an x as @alias said:
x(9x + 3) = 0
now set each equal to zero:
x = 0, 9x + 3 = 0

solve the one on the right, the other is already x=0

Answer 13

Take the integral:
sin(x) cos^2(x) dx

For the integrand sin(x) cos^2(x), substitute u = cos(x) and du = -sin(x)dx:
=-u^2 du

The integral of u^2 is u^3/3:
=-u^3/3 + constant

Substitute back for u = cos(x):
=-1/3

Answer 14

^why is there a random calculus solution....

Answer 15

Is that related to the problem? O.O

Answer 16

lol!