Question

Sigma Notation?

Answer 1

since this sum is in the first degree, what's the formula?

Answer 2

i dont know...

Answer 3

here, go to this link on UC Davis
https://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/summationdirectory/Summation.html

Answer 4

it's n(n+1)/2

Answer 5

okay!

Answer 6

yup, so sum of 3n + 2 = 3 times sum of n + 2

Answer 7

so...
3 (14*(15)/2) + 2 = your answer

Answer 8

thank you!

Answer 9

\[\sum_{n=1}^{14}3n+2 = \sum_{n=1}^{14}3n + \sum_{n=1}^{14}2 = \\ 3\sum_{n=1}^{14}n + \sum_{n=1}^{14}2\]

Answer 10

So it's supposed to be \(3\left( \dfrac{14(15)}{2}\right) + 14(2)\)

Answer 11

@alias @madisonnvictoriaa

Answer 12

Huh... Yes, you are right. Totally forgot to take the constant into account. It's been 3 years since I had to deal with summations :P

Answer 13

haha that's ok.