Could someone please help me with this organic chemistry question?
Calculate the amount of charcoal required to effectively decolorizethe salicylic acid. Information given to me; - crude salicylic acid= 1g, containing 0.2% Alizarin Yellow R - (not sure if this is important, but we add 25ml of water) - activated 1g of charcoal has an area of 800m2 - area of contact of Ali Yellow R is approximately 200A2 (A=1x10-10m) - alizarin yellow R (M.W. of 287.23, formula isC13H9N3O5) Question (has 4 parts) a) Calculate weight of Alzarin Yellow R in the 1g sample ofsalicylic acid. b) Convert this to the number of moles, and thence the # ofmolecules. c) Calculate the total area occupied by these molecules. d) Calculate the weight of activated charcoal needed that would provide this area.
im sorry but i don't no this im sorry
do u who does?
ummmm let me see if i do
@Whitemonsterbunny17 @elementwielder @CrazyCountryGirl
im sorry but i wouldn't know...
I'm soooo sorry, but I don't know chemistry. :/
ya im a freshman so i haven't learned advanced chemistry yet
do u know anyone who knows this?
IDK IM ONLY IN 8TH GRADE. :)
well, for a) you know that the mass percentage of your substance of interest is 0.2%, so multiplying this by the total mass of salicylic acid (1g) should get you the answer
You were given the molecular weight of the compound, use the mass in the answer in part a to solve for the number of mol. After you get mol, multiplying it by avogadro's number (6.02 x 10^23)
for c, multiplying the number of each molecule with the area that each can go in contact with. I'm not sure about the part where you say "200A2" and A = 1 x 10^-10 tho... But yes, multiply the answer in b (total number of molecules) with the area
and for d, you just need to know the mass of activated carbon needed to neutralized it. Since you know 1g of charcoal covers 800m^2, just set up an expression to equate it with the total area of salicylic acid you have. 800x = answer in c
solve for x, and voila! If you still have questions, ask me :)
And although this is a hard problem, it technically does not require ANY knowledge of chemistry. It's just math, and simple math at that :/ The key to solve these problems is if you are patient and can think critically down to the fundamental levels.
@alias could u come help me
here is what i have so far
a) 0.002g b)69.63 x 10^-6 mol c) 4.19 x 10^-18 m^2/molecule
so you're stuck on d?
and remember, for b you're solving for the total number of molecules, not mols
and now with the new b, solve for c again
d is just 800x = answer in c. Just solve for x
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