Question

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Answer 1

\[\huge \int\limits_{-4}^{-1}\frac{ \pi }{ 2 }d \theta \]

Answer 2

pi/2 is a constant

Answer 3

I have just started it . I am clueless

Answer 4

so if you integrate it, it's just pitheta/2

Answer 5

\[\huge \int\limits \frac{ \pi }{ 2 }d \theta \ =>\frac{ \pi \theta }{ 2 }+C\] I'm assuming you know how to deal with limits of integration?

Answer 6

That is DEFINITE INTEGRATION

Answer 7

see the question

Answer 8

Read what I said after I integrated it.

Answer 9

@╰☆╮Openstudier╰☆╮ relax a little and let us help lol

Answer 10

For theta we have to substitute these values That's what i think no one taught these to me i am just figuring things on my my own.

Answer 11

That's fine, and yes you're correct!

\[\huge \frac{ -\pi }{ 2 }-\frac{ -4\pi }{ 2 } => \frac{ 3\pi }{ 2 }\]

Answer 12

So that's your final solution, and when I meant backwards I meant to put,
\[\huge \frac{ \pi \theta }{ 2 }|_{-4}^{-1}\]

Answer 13

\[\huge \int\limits_{a}^{b} c dx = c(b-a) \] where c is a constant, basically.

Answer 14

Thank you for help , these may seem basic problems but no one taught me integration i am just assuming how things work

Answer 15

It's fine :P, we all start somewhere.

Answer 16

batman deserves more medals :P

Answer 17

lol

Answer 18

Well done @iambatman ! Good work.

Answer 19

Thanks haha.

Answer 20

LOL thanks for helping my brother actually he used my account to ask the question , i will ask him to create a new account
lol

Answer 21

Lol @iambatman