Question

s^2-3s/s^2+s-12 (divided by) s+6/s+4? I need to factor it out. Here are the answer choices: A.s-3/s-6 B.s-3/s^2+6s C.s+6/s D. s/s+6

Answer 1

s^2 - 3s , both have an "s" in common, factor it out

--> s(s-3)

s^2 + s- 12, find 2 numbers that multiply to -12 but add to 1

--> (s + ?)(s + ?)

Answer 2

Is this the problem?

\(\dfrac{s^2 - 3s}{s^2 + s - 12} \div \dfrac{s + 6}{s + 4} \)

Answer 3

Yes,That's the problem

Answer 4

@dumbcow So,would the factors be -3,and 4?

Answer 5

Factor the left numerator by simply factoring out s.
Factor the left denominator like @dumcow showed above.
Then replace the division sing with a multiplication sign and flip the second fraction.

Answer 6

Correct, use -3 and 4.

Answer 7

Could I factor the s^2-3s with 1 and 3?

Answer 8

s^2 - 3s , both have an "s" in common, factor it out

--> s(s-3)

Answer 9

No. That is simply factoring out an s as @dumbcow showed you earlier.

Answer 10

After factoring the entire left fraction and flipping the right fraction and changing the division into a multiplication, you should have this:

\(\dfrac{s(s - 3)}{(s + 4)(s - 3)} \times \dfrac{s + 4}{s + 6} \)

Answer 11

Then the s+4's cancel out

Answer 12

correct

Answer 13

then do the s-3's cancel too?

Answer 14

then the answer is s/s+6?

Answer 15

Yes.

\(\dfrac{s\cancel{(s - 3)}}{\cancel{(s + 4)}\cancel{(s - 3)}} \times \dfrac{\cancel{s + 4}}{s + 6}\)

\(= \dfrac{s}{s + 6} \)

Answer 16

Good job!

Answer 17

Okay,Thank you guys so much!

Answer 18

You're welcome.