triangle ABC has been rotated 90° to create triangle DEF. Using the image below, prove that perpendicular lines have opposite and reciprocal slopes.
@phi @ganeshie8 @.Sam.
start by finding the slope of BC
How do I do that?
use slope formula
look at the given diagram, can u tell the coordinates of B and C ?
B = (?, ?) C = (?, ?)
B = (4, 5) C = (1, 1)
Excellent !
next, find the slope of BC using slope formula : slope = \(\dfrac{y_2 - y_1}{x_2-x_1}\)
B = (4, 5) x1 y1 C = (1, 1) x2 y2
slope of BC = \(\dfrac{1-5}{1-4} = \dfrac{-4}{-3} = \dfrac{4}{3}\)
After 90 degree rotation, this BC has moved to EF, find the slope of EF also same way as above^
first get the coordinates of E and F
E = (-5, 4) F = (-1, 1) Slope of EF = \[\frac{ 1 - 4 }{ -5 - -1} = \frac{ -3 }{ -4 }\]
small mistake, let me correct
E = (-5, 4) x1 y1 F = (-1, 1) x2 y2
slope of EF = \(\dfrac{1-4}{-1 --5} = \dfrac{-3}{-1+5} = \dfrac{-3}{4}\)
compare this slope with the earlier slope of BC
aren't they reciprocals wid opposite signs ?
I don't understand how they're reciprocals if they have negative numbers.
slope of BC = \(\dfrac{4}{3}\) slope of EF = \(\dfrac{-3}{4}\)
stare at both of them
you can get one from the other by : 1) taking reciprocal, and 2) flipping the sign
I understand they're recipricoles, but the -3 isn't the same in the BC
thats the reason we call them reciprocals wid opposite signs
Okay, I understand. Thank you.
actually we call them "negative reciprocals" or "opposite reciprocals"
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