WILL MEDAL AND FAN The volume of a square based pyramid is eighty-one cubic meters. What is the volume of the cube with the same side length and height
3*81
is 243
a cube with side length s has a volume of s^3 a pyramid with the same side length base is (1/3)s^3... pyramids are always 1/3 the volume of their corresponding prisms...
that goes for cones and cylinders as well...
so what is the equation i must do?
Wait, is the answer 243
:) yes...the answer is 243 cubic meters
m squared
m cubed...volume.
thank you, iwill medal and fan you
do you think you can help me with one more
i can give it my best shot
What is the new volume of a rectangular prism that is originally twelve cubic meters and is then resized using a scale factor of 3 on each side length
so a rectangular prism has a volume formula of \[V=lwh\] so if each of these goes up by a factor of 3, your new formula would be \[(3l)(3w)(3h) = (3)(3)(3)(lwh)\]
if your original prism (lwh) was 12, what would the new volume be?
i believe the answer is 36m
not quite...each of the sides was made bigger by a factor of 3. notice i have 3 times 3 times 3 in my post?
well 3*3*3 is 27.. so what do i do from here
you see in my post where i have \[(3)(3)(3)(lwh)\] (lwh) is the vloume from your original prism...multiplying it by the (3)(3)(3) is the volume of the *new* prism...
Yes, increasing lengths by factor k increases areas by k^2 and volumes by k^3.
would this answer be around 110? my calculations are a little off
no...that's way off...tell me what calculations you are doing...
im sorry, im not very good if its not multiple choice
that's ok...we can get you there...tell me how you came up with 110 so i can see where the disconnect is.
i did meant 100, i did 27*3 and got 81, so i rounded to the nearest hundredth and asked if it was near there
show the choices u have
it is not multiple choice
oh
ok...let's take a step back. your original prism had a length, a width and a height...and the volume, we know, is 12 with me so far?
yes
now we don't know the l, w, and h...and frankly, we don't care. what we *do* know is that we have another prism and this one has a length, width and height each 3 times the original prism. still tracking?
i believe so
lol...good enough for now. what we need to figure out is what is the volume of the *new* prism. so let's look at the formula for a rectangular prism... \[V=lwh\] simple enough, right?
yes
so our original prism had sides l, w, and h and V=12 \[12=lwh\] and we know that the new prism has sides (so we don't confuse with the first one) x, y, and z where x=3l y=3w z=3h do you see where i get that? this is the crucial piece...
i understand this part now.
good :) so using the same volume formula the new prism would have \[V=xyz=(3l)(3w)(3h)=(3)(3)(3)(lwh)\]
if we plug 12 in for lwh (since that is the volume of the original prism) we would have the volume of the new one, yes?
324!!!
perfect!
Thank you so much
and i have fanned you
you're quite welcome...i told you we would get you there
Yup, have a good day
you too
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