Help! Fan and medal for best answer! Please hold on while I attach the image. Triangle ABC below is reflected across the y-axis and then translated 1 unit right and 2 units down. a) Write the coordinates of the vertices of the image after reflection. b) Write a rule for the translation. Use narrow notation. c) Write the coordinates of the vertices of the new image after translation.
That's the image
A= (1, 3) B= (4, 5) C= (3, 1) right?
now reflection over y-axis , means keep all y co-ordinates same, and flip the sign of all x co-ordinates. (x,y)→(−x,y)
so A' = (-1, 3) B' = (-4, 5) c' = (-3, 1) yes or no?
Yes sid is correct
Now we have to move them 1 to the right so we should add 1 to all the x coordinates.and the new coordinates will be= A'= (0, 3) B'(-3, 5) C'(-2, 1). do u get it so far??
@sidsiddhartha is that part a,b, and c?
part (a) A' = (-1, 3) B' = (-4, 5) c' = (-3, 1) part (b) here u have to use the arrow notation so\[(x,y)\rightarrow(-x,y)\]
Yes I got that part
and for part(c) we have to move them 1 to the right so we should add 1 to all the x coordinates.and the new coordinates will be= A'= (0, 3) B'(-3, 5) C'(-2, 1).
then we have to move them down two so we should make each y value 2 less. so now they will be A'= (0, 1) B'= (-3, 3) C'= (-2, -1) that's all
So part C is A'= (0, 1) B'= (-3, 3) C'= (-2, -1)
u can also use a arrow notation for patr (c) like this (A', B')-->(x+1, y-2) yup that's ur answer
Thank u
np :)
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