Question

Help me on this problem
(Intemediate level)

Answer 1

\[\huge \log10(x-1)^{3} - 3\log10(x-3)= \log 10(8)\]

Answer 2

\[Find \huge logx(625)\]

Answer 3

Solution
log10 (8) - 1/3 Log10 (x) = log10 (2)
or, log10(8) - log 10 (x^1/3) = log10 (2)
or, log10 (8/x^1/3) = log 10 ( 2)
Equating both side we get
( 8/ x^ 1/3 ) = 2
or 4 = x^ 1/3
solving the above equation we get
x = 4 ^ 3
==> x = 64

Answer 4

I am getting 4 as the answer

Answer 5

@iambatman

Answer 6

@Zale101

Answer 7

@satellite73

Answer 8

i can't read this sucker

Answer 9

\[ \log(x-1)^{3} - 3\log(x-3)= \log (8)\] like that?

Answer 10

yes

Answer 11

sucker ?

Answer 12

ok lets write it as a single log

Answer 13

I am getting 4

Answer 14

\[\log\left(\frac{(x-1)^3}{(x-3)^3}\right)=\log(8)\]

Answer 15

this looks ugly so lets make it look like
\[3\log(\frac{x-1}{x-3})=\log(8)\]

Answer 16

nope, i like it better the other way

Answer 17

I am getting 4 as the answer

Answer 18

get
\[(\frac{x-1}{x-3})^3=8\] and so
\[\frac{x-1}{x-3}=2\]

Answer 19

seems unlikely, let me check it

Answer 20

\[x-1=2(x-3)\\
x-1=2x-6\\x=5\]

Answer 21

logx(625)
x=4

Answer 22

oooh ok i didn't see the last part

Answer 23

\[\log_5(625)=4\] got it

Answer 24

Thank you for help!!

Answer 25

yw
you did all the work