Question

calc question #2 lol

Answer 1

Do you know how to differentiate?

Answer 2

did you try to explicitly differentiate the equation of the curve ?

Answer 3

yah isnt it....

Answer 4

e^x+3x+2y(dx/dy)=0?

Answer 5

derivative of x^3 is 3x^2
every thing else is correct! :)

Answer 6

In this question, you have to differentiate the curve to find the slope of the curve at all 'x'.
And then substitute '0' for the x and '3' for the y to get the slope at (0,3).

Answer 7

then just plug in x=0, y= 3 in that

Answer 8

hold on

Answer 9

also
derivative of
y^2 will be 2y dy/dx
isn't it ?

Answer 10

1?

Answer 11

for some reason thats not one of my answer choices

Answer 12

keep dy/dx as it is.
as it will be the slope of tangent at 0,3

e^0 + 3*0 +2(1) dy/dx = 0

get slope = dy/dx from here

Answer 13

its not right

Answer 14

@AkashdeepDeb

Answer 15

dy/dx=1...

Answer 16

yeah, 1 is not correct
but did you try getting dy/dx from here ?
e^0 + 3*0 +2(3) dy/dx = 0

Answer 17

e^0 =1

1+6dy/dx = 0

dy/dx =....?

Answer 18

1/6?

Answer 19

thnxs

Answer 20

you would first SUBTRACT 1 from both sides, right ?
6 dy/dx = -1

dy/dx = -1/6

Answer 21

and we are not done yet :P

Answer 22

ok

Answer 23

we need slope of normal
which is perpendicular to tangent

Answer 24

slope of tangent = -1/6
any ideas on how to get slope of normal ?

Answer 25

y-f(a)=f'(a)(x-a)???

Answer 26

just a simple rule

Product of slope of perpendicular lines = -1

Answer 27

so,
slope of normal = m

m*(-1/6) = -1

find m from here

Answer 28

m-6

Answer 29

did you mean m=6 ?

Answer 30

yah

Answer 31

then you're correct! :)

Answer 32

awsome thankyou, can u help me with another if I post it?

Answer 33

sure :)

Answer 34

ok ill post it in a new question