can someone please help me with algebra 2b? i will medal AND fan!! (picture posted below)
Very often a picture is helpful.
|dw:1399996384297:dw|
i dont get what your trying to show me..
First, let's figure out what we need to do. The drawing will help.
what do we do first?
The satellite goes around the Earth in 24 hours. If we can find the distance of its orbit, then we will have a distance and a time, and we can find its speed.
The distance is the circumference of the large circle in the drawing.
r is the radius of the Earth, which you are given. d is the distance of the satellite from the Earth. You are also given this. If you add r and d, you will have the radius of the circle which is the orbit of the satellite.
Then using the radius of the orbit, you can find the circumference of the orbit. That is the distance the satellite travels in 24 hours.
First step, let's find the radius of the orbit. R = r + d = 6400 km + 35,800 km = 42,200 km So far you understand?
We have a circle with a 42,200 km radius. What is the circumference of the circle? |dw:1399997612588:dw|
Are you still there?
yep:)
sorry i was away for a while..:/
I also had to go away, but now I'm back. Use the radius of the orbit of the satellite to find the circumference of the orbit. The circumference of a circle is \(C = 2 \pi r\) The radius of the orbit is 42,200 km. \(C = 2 \times 3.14159 \times 42,200~km\) C = 265,150 km That means the satellite travels 265,150 km in 24 hours. Since we have a distance and a time, we can find a speed. \(speed = \dfrac{distance}{time} \) \(speed = \dfrac{265150~km}{24~hours} \) \(speed = 11,048 ~km/h\)
Now multiply each amount of time given in the question by the speed to find how far the satellite travels in each period of time.
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