Algebra
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OpenStudy (anonymous):
help please. Adding and Subtracting Rational
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OpenStudy (anonymous):
OpenStudy (anonymous):
@mathmale @iPwnBunnies please explain?
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
can you please explain
ganeshie8 (ganeshie8):
first, get a common denominator for both fractions
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OpenStudy (anonymous):
9x^2 ?
ganeshie8 (ganeshie8):
\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\]
ganeshie8 (ganeshie8):
multiply and divide the second fraction by \(x\) so that you get same denominator for both fractions
OpenStudy (anonymous):
am i right?
ganeshie8 (ganeshie8):
\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\]
\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\times \dfrac{x}{x}\]
\[\dfrac{5}{3x^2} + \dfrac{9x}{3x^2}\]
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OpenStudy (anonymous):
ohh okay
OpenStudy (anonymous):
so then do i just add across?
ganeshie8 (ganeshie8):
Now that the denominators are equal, you can add the fractions by simply adding the numerators
ganeshie8 (ganeshie8):
\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\]
\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\times \dfrac{x}{x}\]
\[\dfrac{5}{3x^2} + \dfrac{9x}{3x^2}\]
\[\dfrac{5+9x}{3x^2} \]
OpenStudy (anonymous):
14x/3x^2
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ganeshie8 (ganeshie8):
lol you cant combine apples and coconuts like that
OpenStudy (anonymous):
okay so just c
OpenStudy (anonymous):
yay thank you!!!
ganeshie8 (ganeshie8):
`5` and `9x` are not like terms,
so u cant combine them. leave they separately like that ^
ganeshie8 (ganeshie8):
yw
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OpenStudy (anonymous):
ohh yay you were a huge help i think i can do it now
ganeshie8 (ganeshie8):
good :)