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Algebra 16 Online
OpenStudy (anonymous):

help please. Adding and Subtracting Rational

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathmale @iPwnBunnies please explain?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

can you please explain

ganeshie8 (ganeshie8):

first, get a common denominator for both fractions

OpenStudy (anonymous):

9x^2 ?

ganeshie8 (ganeshie8):

\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\]

ganeshie8 (ganeshie8):

multiply and divide the second fraction by \(x\) so that you get same denominator for both fractions

OpenStudy (anonymous):

am i right?

ganeshie8 (ganeshie8):

\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\] \[\dfrac{5}{3x^2} + \dfrac{9}{3x}\times \dfrac{x}{x}\] \[\dfrac{5}{3x^2} + \dfrac{9x}{3x^2}\]

OpenStudy (anonymous):

ohh okay

OpenStudy (anonymous):

so then do i just add across?

ganeshie8 (ganeshie8):

Now that the denominators are equal, you can add the fractions by simply adding the numerators

ganeshie8 (ganeshie8):

\[\dfrac{5}{3x^2} + \dfrac{9}{3x}\] \[\dfrac{5}{3x^2} + \dfrac{9}{3x}\times \dfrac{x}{x}\] \[\dfrac{5}{3x^2} + \dfrac{9x}{3x^2}\] \[\dfrac{5+9x}{3x^2} \]

OpenStudy (anonymous):

14x/3x^2

ganeshie8 (ganeshie8):

lol you cant combine apples and coconuts like that

OpenStudy (anonymous):

okay so just c

OpenStudy (anonymous):

yay thank you!!!

ganeshie8 (ganeshie8):

`5` and `9x` are not like terms, so u cant combine them. leave they separately like that ^

ganeshie8 (ganeshie8):

yw

OpenStudy (anonymous):

ohh yay you were a huge help i think i can do it now

ganeshie8 (ganeshie8):

good :)

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