Question

Help please.

Answer 1

@bek_love

Answer 2

just a second.

Answer 3

ok

Answer 4

ok. so the easiest way to do these types of problems is to factor it out completely.
the top would be sqrt(3*2*x*x*x*x*x*x*x*x*y*y*y*y*y*y*y*y*y) you then do the same to the bottom of the equation. sqrt(5*x*x*y*y*y*y) you can then eliminate.

Answer 5

problem is I don't think that that is the type of answer they want based on the answer choices given... just a second.

Answer 6

yeah!!! its working!!! but for how long -_-
okay... so when you eliminate in the equations you would get sqrt(6x^6y^5)/sqrt(5)
you then have to get rid of the radical in the denominator.

Answer 7

to get rid of the radical in the denominator you have to multiply the entire fraction by a fraction that would make the denominator a perfect square. \[\frac{ \sqrt{6x ^{2}y ^{5}} }{ \sqrt{5} }\times \frac{ \sqrt{5} }{ \sqrt{5}}\]

Answer 8

it is supposed to be \[\frac{ \sqrt{6x ^{6}y ^{5}} }{ \sqrt{5} }\times \frac{ \sqrt{5} }{ \sqrt{5}}\]
you would then get \[\frac{ \sqrt{30x ^{6}y ^{5}} }{ 5 }\]

Answer 9

so it would be D none :o

Answer 10

exactly. if I'm wrong I have no idea what they want because as far as I know you can't reduce that any further.

Answer 11

ahh thank you so much for helping, can you help with a couple more ;O

Answer 12

I would love to help but I am in the middle of a test myself so...

Answer 13

oh okay :) thanks anyways

Answer 14

can you message me when your done?

Answer 15

yeah but it might be awhile :)