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OpenStudy (anonymous):
Let's see how you're at calculus ;). Differentiate the following function:
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OpenStudy (anonymous):
\[f(x)=\ln(x^2+10)\]
OpenStudy (anonymous):
\[\frac{ d }{ dx }\ln x=\frac{ 1 }{ x}\]
OpenStudy (anonymous):
good job, surjthayer!
OpenStudy (anonymous):
Next medal goes for the person who can explain it.
OpenStudy (anonymous):
I wonder if this is your problem or you actually wondering if someone can do it.
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OpenStudy (anonymous):
Not you Surj, you had your medal cheeky. ;)
OpenStudy (anonymous):
If people can actually do it.
OpenStudy (anonymous):
\[\huge f(x) = \ln(x^2+10)\]
\[\huge f'(x) = \frac{ 1 }{ 10+x^2 }\times (10+x^2)'\]
\[\huge = \frac{ 2x }{ x^2+10 }\]
OpenStudy (anonymous):
correct. took natural logarithms on bothside, differentiated with respect to x, and found the derivative. splendid job iambatman as well as surjthayer
OpenStudy (anonymous):
Yes (d/dx) [f(u(x)] = [1/u(x)](du/dx]
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OpenStudy (anonymous):
Next challenge or no-go?
OpenStudy (anonymous):
Next challenge or no-go?
OpenStudy (anonymous):
Now opening new question.
OpenStudy (anonymous):
Now opening new question.
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