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what is 5e^4x=535
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divide both sides of the equation by 5 then take the ln of both sides of the equation... then the last step is to divide both sides by 4 hope it helps
Thanks but is actually is a..solve the exponential equation by taking the logarithms on both sides...
ok... so dividing by 5 and you get \[e^{4x} = 107\] take the log of both sides \[\ln(e^{4x}) = \ln(107)\] applying the log laws for powers \[4x \ln(e) = \ln(107)\] and when the base of the log and base of the exponent are the same you get 1 \[\log_{a}(a) = 1\] so you have 4x = ln(107) now solve for x
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