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Physics 13 Online
OpenStudy (anonymous):

HELPPPPP

OpenStudy (anonymous):

OpenStudy (anonymous):

@Ashleyisakitty

OpenStudy (anonymous):

@radar

OpenStudy (anonymous):

@douglaswinslowcooper

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@Saeeddiscover

OpenStudy (anonymous):

I think I answered this question for someone else! Let me see if I can find it.

OpenStudy (anonymous):

It's probably just easier to answer it again. Do you know the equations of motion for constant linear acceleration? Something like this...\[x = x_0 + vt + {1 \over 2} at^2\]

OpenStudy (anonymous):

no ;/

OpenStudy (anonymous):

what you know is u the initial speed a the acceleration,which is negative v the final velocity,which is zero you have to find the s the distance travelled use equation of motion v^2 - u^2 = 2as you will get the answere

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