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Mathematics 14 Online
OpenStudy (anonymous):

What is the length of the focal width? x^2=12y

OpenStudy (anonymous):

the only number you see

OpenStudy (anonymous):

12?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

ooohhh ok but how?

OpenStudy (anonymous):

i mean why?

OpenStudy (campbell_st):

the standard form is \[x^2 = 4ay\] you need to find a, the focal length... the chor passing through the focus is called the focula chord or latus rectum and has a length 4a hope it helps

OpenStudy (campbell_st):

oops sorry for the typos... focal chord...

OpenStudy (anonymous):

guess that is just what it is called if you have \[(x-h)^2=4p(y-k)\] then the focal length is \(|4p|\) oh maybe i had that confused with "focal width" @campbell_st am i wrong? it is 3 in this case?

OpenStudy (anonymous):

oh yes, focal length, not focal width, sorry

OpenStudy (campbell_st):

they are the same thing.... I just love the term latus rectum....

OpenStudy (anonymous):

lol

OpenStudy (campbell_st):

focal length... is.. vertex to focus...

OpenStudy (anonymous):

ok im starting to undertsand it more but this is helping out alot

OpenStudy (anonymous):

so 12? lol

OpenStudy (campbell_st):

thats it...

OpenStudy (anonymous):

thanks guys!!

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