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Mathematics 20 Online
OpenStudy (anonymous):

Find the standard form and x-intercepts of the function. f(x) = x^2 + 3x + 4 My answers are: standard form -(x + 3/2)^2 + 25/4 and x-intercepts (-4, 0), (1,0) Did I solve this correctly?

OpenStudy (anonymous):

no it"s wrong

OpenStudy (anonymous):

can you please help me how to do it?

OpenStudy (anonymous):

it become (x+(3/2))^2-(25/4)

OpenStudy (anonymous):

i am sorry I typed the problem wrong: it should be f(x) = -x^2 + 3x + 4

OpenStudy (anonymous):

now it's right

OpenStudy (anonymous):

oh, thanks

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