The path of a model rocket can be represented by the equation h(t) = - t2 + 15t + 16, where h(t) is the height, in feet, of the rocket at any given time, t. What is the height of the model rocket after 3 seconds from launch?

Question

anonymous · Answer

i would reply if i knew the problem solve

johnweldon1993 · Answer

So we have

$$\large h(t) = -t^2 + 15t + 16$$

and they want to know what h(t) equals when t = 3...so we just plug in 3 for every 't' we see

$$\large -(3)^2 + 15(3) + 16 = ?$$

anonymous · Answer

oh ok