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Trigonometry
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Solve the triangle f a=4, b=3, and A=36(degrees) (find c, B, and C)
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Use cosine law: a^2 = b^2 + c^2 - 2bc cosA Isolate c, and solve for c. After solving for C, you can easily solve for the remaining angles by using cosine or sine law. Depends on your choice.
I don't understand how to work it out. Can you walk me through the steps?
Where are you stucked?
\[c ^{2}=4^{2}+3^{2}-2*4*3\cos36 ... that is the formula but how do I evaluate \it? Pemdas?\]
like, I think exponents, then the basic math. Then I have c^2=1cos36... thats not right
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Well it will become: c^2 - 6c cos 36 = 4^2 - 3^2 c^2 - 6c cos 36 = 7 c^2 - 6c cos 36 - 7 = 0 Apply quadratic formula to solve for C.
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