Question

check? @johnweldon1993

Answer 1

b

Answer 2

im gonna hurt you lol

Answer 3

dont ask y it just is

Answer 4

Hint...when you are dividing by a fraction...flip the fraction and turn this into multiplication

\[\large \frac{3x^3}{4y} \times \frac{9y}{x}\]and solve

Answer 5

so just multiply straight across...what do you get?

Answer 6

27x^3y/4xy ?

Answer 7

Perfect...so we have

\[\large \frac{27x^3y}{4xy}\]

see anything that can cancel out?

Answer 8

x and y

Answer 9

or just ?

Answer 10

y

Answer 11

Well...the 'y' yes....

\[\large \frac{27x^3\cancel{y}}{4x\cancel{y}}\]

so we have

\[\large \frac{27x^3}{4x}\]

anything else?

Answer 12

Hint** notice that the top and the bottom have at least 1 'x'

Answer 13

the x i think

Answer 14

Right...but notice the top....has 3 'x' ...because

\[\large x^3 = x \times x \times x\] right?

so really what we have is

\[\large \frac{27 x \times x \times \cancel{x}}{4\cancel{x}}\]

which leaves us with

\[\large \frac{27x^2}{4}\]make sense?

Answer 15

yay yes it does you should like come to south bend and tutor mer lol

Answer 16

Lol I do so much tutoring at my university as it is XD

Answer 17

nooo come here lol i need a lot of help and not just mentally lol

Answer 18

check it out,friend......