9 students volunteer for a committee. How many different 2-person committees can be chosen?
so you know from the problem you can have 2 students in a group
if you divide 9 /2, you get a fraction but we can't have a fraction of a group so take the nearest whole number
In this case, order is not important. Let's say the students are named A through I. Having A and B in a committee is the same as having B and A in the committee.
I Got 36 ?
I wonder as I went through that logic if this problem is a little more complicated than it appears to be
The answer choses are a.362,880 b.1 c.72 d.36
would you need to know how many students there are to find how many committees?
You need \(_9C_2\). In general, \(_nC_r = \dfrac{n!}{(n - r)!r!}\) \( _9C_2 = \dfrac{9!}{(9 - 2)! 2!} \) \(= \dfrac{9 \times 8 \times \cancel{7!}}{\cancel{7!}\times 2} \) \(= 36\)
You are correct, 36 is the answer.
alright thank you guys !
wlcm
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