Question

given that y(x)= sqrt of 4x-1 and v(x) = x-5, what is the domain of u(v(x))

Answer 1

can you find u(v(x) first?

Answer 2

well wouldn't u(v(x)) be ( sqrt of 4x - 1)(x-5) ?

Answer 3

NO u(x) = sqrt of 4x-1and v(x) =x-5
now u(v(x)) replace x in u(x) with v(x)
which gives you sqrt(4(x-5) -1)

Answer 4

for the domain value inside sqrt should be greater than zero
so 4(x-5)-1 >0
Can you solve now?

Answer 5

oh alright. Would it be 5.25? (or 21 over 4 for fractional form)

Answer 6

it will be inequality

Answer 7

x> 21/4

Answer 8

Answer is secondary did you get understand the method to solve it