Question

can someone show me how to do this???

Answer 1

@mathslover

Answer 2

look

Answer 3

Sierra, you just have to think that : for what value of y, does the equation becomes infinity or undefined. General forms may be like 1/0 or 0/0 or (anything)/0

Answer 4

So, first of all , think that when will the denominator equal to zero? i.e. when will y-3 = 0 ?

Answer 5

y+3=0

Answer 6

wait

Answer 7

Oh yes @gegomohamed , good point. Sorry, I went wrong there.

Answer 8

okay^^

Answer 9

after you take the common factor 3y what?

Answer 10

@gegomohamed

Answer 11

ok i'll tell you

Answer 12

we better take y not 3y i tell you why

Answer 13

because it will be \[\frac{ y(3y-3) }{ y-3 }\]

Answer 14

okay

Answer 15

then?

Answer 16

@mathslover help me
Am i right to here ??

Answer 17

Sorry, I was not online, so can't respond.

Well, you can simplify it like this :


\(\dfrac{3y(y-3)}{(y-3)}\) = \(\dfrac{3y\cancel{(y-3)}}{\cancel{(y-3)}}\) = 3y

Answer 18

thank you^^^