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What is the slope of the polar curve r=cos(2 theta) at theta =0 and theta=pi/2. (This is Calculus II)
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dr/d,theta
it may be simpler in this case to just convert it to xy coords
parametric xy coords that is
cos(2t) = cos^2(t) - sin^2(t) = 2cos^2(t) - 1 x = r cos(t); y=sin(t); r^2 = x^2 + y^2 those might play into a parametric solution
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