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Mathematics 15 Online
OpenStudy (anonymous):

3^2x=27

OpenStudy (anonymous):

9x=27 27/9=3 x=3

OpenStudy (anonymous):

Can you explain how you did that

OpenStudy (yttrium):

\[3^{2x} =3^3\] Hence, x = 3/2

OpenStudy (yttrium):

The given expression is same as the expression I gave in my first reply ^

OpenStudy (anonymous):

If you substituted x for 3, the statement would be true. 3^2*3=27 9*3=27 27=27

OpenStudy (anonymous):

I don't understand this at all

OpenStudy (anonymous):

Where did you get the 9 from

OpenStudy (yttrium):

I believe the question is like 3^(2x) = 27 @DJ♬Øϟϟ¥

OpenStudy (anonymous):

Can you solve 3^(2x)=27 and explain every step this is new material for me and i'm completely lost

OpenStudy (yttrium):

Well. This part is not that difficult. The left hand side is of base three? and we know that 27 (which is in the right hand side) is also convertible to base 3.We know that 27 = 3^3 Hence, we can use this equation: \[3^{2x} = 3^3\] from that, we can conclude that\[2x = 3\] and hence x = 3/2

OpenStudy (anonymous):

i dont understand where you got 2x=3

OpenStudy (yttrium):

i got this from 3^(2x) = 3^3 since, the base in the left and right hand side are both 3, hence we can just equation their exponents. thats why we had 2x = 3

OpenStudy (anonymous):

ohhh thank you i understand

OpenStudy (yttrium):

Np

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