Question

help :c

Answer 1

Use basic identities to simplify the expression.
\[\frac{\tan \theta }{ \cot \theta } \]

Answer 2

\[\large \cot\theta=(\tan\theta)^{-1} \]

Answer 3

so tan0/tan0^-1 wouldnt you multiply the denominator by the numerator and it would cancel out?

Answer 4

no

Answer 5

\[\large \frac{\tan\theta}{\cot\theta}=\frac{\tan\theta}{(\tan\theta)^{-1}}=\tan^2\theta \]

Answer 6

.-. how did you get ^2 from ^-1

Answer 7

\[\large \frac{\tan\theta}{(\tan\theta)^{-1}}=\frac{\tan\theta}{\frac{1}{\tan\theta}}
=\tan^2\theta \]

Answer 8

oh okay that makes sense c: thank you

Answer 9

u r welcome