sqrt(x+6) = sqrt(x – 10)-3
\(\sqrt{x+6} = \sqrt{x-7} -3\)
You need to start by squaring both sides of the equation. \[(\sqrt{x+6})^2 = (\sqrt{x-7} - 3)^2\]
\[x+6 = (\sqrt{x-7} - 3)(\sqrt{x-7}-3)\]
Expand and then isolate the remaining square-root on one side of the equation. Square both sides again. Then, isolate x.
can you please do one more step
\[x+6 = (x-7) -3\times\sqrt{x-7} - 3\times\sqrt{x-7}+9\] \[x+6 = x-7 - 6\times\sqrt{x-7} + 9\]
thank you
However....no solutions exist.
Did you type the problem correctly, or is that a possible answer (multiple choice)? Else, if this is hand-written homework, I would just write that there are no solutions.
does this one has a solution
sqrt(x+6) = sqrt(x – 10)-3
http://www.wolframalpha.com/input/?i=sqrt%28x%2B6%29+%3D+sqrt%28x+%E2%80%93+10%29-3+solve+for+x
thank once again
No problem. :)
Thanks. :)
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