Find the equation of the line that is parallel to the line formed by the equation 4x - 3y = -9 and passes through the point (-18, 1)

Question

kkutie7 · Answer

Solve for y. Slope of the new line should be the same as this one. Plug into this y=slope(x-x1)+y1

whpalmer4 · Answer

Rearrange your original line's equation by solving it for $y$.  You'll end up with the equation in slope-intercept form: $$y = mx+b$$where $m$ is the slope and $b$ is the value of the y-intercept.

A parallel line will have an equal slope.  Use the point-slope formula $$y-y_1 = m(x-x_1)$$to write the equation of a line with slope $m$ (as found above) that passes through the point $(x_1, y_1)$ (given by the problem statement).  Rearrange the resulting equation to suit your needs, if necessary.