Mathematics
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OpenStudy (anonymous):
How do we know if a function is 1 to 1. pls explain :)
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OpenStudy (anonymous):
i tell you
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
make a horizontal line test like that
OpenStudy (anonymous):
take out the derivative of that function and check whether it is increasing or decreasing in that interval
OpenStudy (anonymous):
|dw:1400240570214:dw|
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OpenStudy (anonymous):
double derivative?
gegomahmed okie and then?
OpenStudy (anonymous):
mohamed*
OpenStudy (anonymous):
|dw:1400240685064:dw| then this is 1 to 1
OpenStudy (anonymous):
but
OpenStudy (anonymous):
sorry horizontal
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OpenStudy (anonymous):
okie so if it cuts at one point it means its 1 to 1?
OpenStudy (anonymous):
hold on I'll draw it
OpenStudy (anonymous):
i'll upload the question
OpenStudy (anonymous):
ya u upload the question
OpenStudy (anonymous):
the last question. its asking if it has an inverse. the answer is that it does have an inverse since its a 1 to 1 function.
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OpenStudy (anonymous):
this is 1 to 1
OpenStudy (anonymous):
this one not 1 to 1
OpenStudy (anonymous):
so its cutting at one point it means its one to one?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
and the second one is not?
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OpenStudy (anonymous):
yeah (y)
OpenStudy (anonymous):
okie thanks :) so can u check the question?
OpenStudy (anonymous):
sure :D
OpenStudy (anonymous):
give me more details about it
OpenStudy (anonymous):
where is the question?
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OpenStudy (anonymous):
OpenStudy (anonymous):
here :3
OpenStudy (anonymous):
hold on
OpenStudy (anonymous):
i did D: but still didnt understand okie lemme check ur link out :3
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OpenStudy (anonymous):
try to make graph for the 1st part
OpenStudy (anonymous):
yea its the same link dont get it D;
OpenStudy (anonymous):
i did make the graph
OpenStudy (mathmale):
Would you share your graph, please? |dw:1400241402377:dw|
OpenStudy (anonymous):
|dw:1400241476974:dw|