find the probability of choosing a blue marble,then a red marble if the marbles are not replaced the bag contains 4 white,3 blue, and 5 red
hello
First, can you find the probability of choosing a blue marble?
1\4
Alright. Now, we don't add that back in. So now there are only 2 blue marbles in the bag. What's the probability that you'd now draw a red marble?
5/11
Ok. Now, the probability of one happening, and then followed by the other, is just the product of the two individual probabilities. This will be true any time they are independent events. P(A and B) = P(A)P(B)
so 1\4 times 5\11?
Yep. Just multiply them together :)
After that, you're done. That's the probability of drawing a blue, and then drawing a red. If you're not sure of how to multiply them, let me know.
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