Question

Find the x-intercepts of the parabola with vertex (2,13) and y-intercept (0,5). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth.

@eragondragon666 @jlg030597 @agent0smith

Answer 1

is this algebra 2?

Answer 2

No, Algebra 1.

Answer 3

wheres the picture just wondering I can help now that i know what type of math it is

Answer 4

There is no picture =/..

Answer 5

hmmmmmm ok one second

Answer 6

This is all there is..

Answer 7

whats the K stand for?

Answer 8

and the H?

Answer 9

I don't know? Lol. New to this..

Answer 10

I mean ill help you.

Answer 11

Unless agent can help me and you understand.

Answer 12

The vertex is (h, k). Your vertex is (2, 13), plug those numbers in.

Answer 13

SO thatd be (y-13)=0(x-2)^2 right

Answer 14

I'm guessing because that (y-k)=a(x-h)^2 You should be right?


@agent0smith is he?

Answer 15

(y-13)=0(x-2)^2

Yes, but... Where did the 0 come from @jlg030597 ??

Answer 16

look at the picture she posted it confused me

Answer 17

Leave a as a.

Answer 18

(y-13)=a(x-2)^2

Answer 19

Now use the other point you're given, and plug in the x and y values for that point.

Answer 20

so (5-13)=a(0-2)^2

Answer 21

so then youd get -2=a-4

Answer 22

(-2)^2 is not -4

Answer 23

and 5-13 is not -2...

Answer 24

ops then -2=a4

Answer 25

right?

Answer 26

See my last post :P

Answer 27

Then what would it be?

Answer 28

-8=a4

Answer 29

...see my 2nd last post.

Answer 30

coming out as -4=a

Answer 31

start over from here

(5-13)=a(0-2)^2

Answer 32

ok -8=a(-4)

Answer 33

5-13=-8
0-4=-4
so itd come out as 2=a

Answer 34

You made the same mistake i pointed out earlier

Answer 35

what ?

Answer 36

(-2)^2 is not -4

Answer 37

then itd still come out the opposite -2=a

Answer 38

Yep. Now you have a, h, and k, so you have the whole equation.

Plug in y=0 to solve for the x intercepts.

Answer 39

(0-13)=-2(x-2)^2? sorry

Answer 40

Yes, solve for x.

Answer 41

Won't it be a decimal? Considering 13 is an odd number?

Answer 42

-13=-2(x-2)^2
-13=-2(x2-4) is this right so far?

Answer 43

No, divide both sides by -2 first

THEN take the square root of both sides

btw you CANNOT distribute a power of 2 into brackets like you did there. Big mistake.
(x-2)^2 = (x-2)(x-2) = x^2 - 4x + 4 NOT EVER EVER EVER (x^2 - 4)

Answer 44

Oh ops sorry im out of it right now can you help her im starting to get so confused and lost.

Answer 45

So wait I think I got x.. Would it = 4.55?

Evidence and my philosophy of it all..

(0-13)=-2(x-2)^2

so let's break it down ....

4.55-2 = 2.55

That gets rid of (x-2) .. So now we have

-2(2.5495)^2

So what I did was 2.55^2 which = 6.50.

That got rid of (2.55)^2 so now we got left:

-2(6.50) which = -13.

Is this correct??

Answer 46

You have an odd way of going about algebra... do things in the correct order, you appeared to do some kinda trial and error

(0-13)=-2(x-2)^2

divide both sides by -2 first

THEN take the square root of both sides. Don't forget to add a plus or minus sign.

Answer 47

Okay... so..

(0-13)=-2(x-2)^2 ...

Divide both sides FIRST by -2..

Would that leave 6.50 = x^2 ?

Answer 48

Cause a negative divided by a negative (-13) and (-2) finalizes to a positive number, correct? And dividing both sides, thus canceling -2<-(x-2<-)^2

Leaving 6.50=x^2?

Answer 49

No... you can't magically make the -2 inside the brackets disappear.

Answer 50

Lol awh.. Well then, so It'd be 6.50 = (x-2)^2?

Answer 51

Yes now take sqrt of both sides

Answer 52

Okay, so..

13=x-4

Then subtract 4 from both sides so it would be

13-4 = 9 = x

So therefore, 9=x?

Answer 53

6.50 = (x-2)^2

take square root of both sides. What is the square root of x^2? If you know that, then what is the square root of (x-2)^2?

Answer 54

Also, the square root of 6.5 is not 13. Square root does not mean multiply by 2.

Answer 55

Oh.. That's right.. Uhm.. I don't know how to do square root of (x-2)^2.. Can you please tell me? The 6.5 square root is 2.55

Answer 56

Tell me the square root of x^2.

Answer 57

I do not know? Less it's 1...

Answer 58

Tell me the square root of 3^2

Answer 59

3?

Answer 60

Now use that to tell me the square root of x^2.

Answer 61

4? Lol.

Answer 62

Square root of 3^2 is 3.

Square root of x^2 is...

Answer 63

Square root of 5^2 is 5.

Notice the pattern.

Answer 64

OH, so X

Answer 65

So the square root of (x-2)^2 is...

Answer 66

x-2

Answer 67

Now finish.

6.50 = (x-2)^2

Answer 68

What? LOL.. Thought we got rid of ^2?

Answer 69

Finish w/o mistakes from there.

Answer 70

Okay..??

6.50 = x - 2

Add 2 to both sides so

8.50 = x

Answer 71

lol i JUST said finish w/o mistakes from there, and you made a mistake :P

Answer 72

-_- this is annyoing. Lol.. I'm confused.

Answer 73

We already went over how to solve it from here, now do it... we had to sidetrack because you had to learn square roots first:

6.50 = (x-2)^2

Answer 74

That's what I did? You said "x^2" would = x... So this would be "6.50 = (x-2)"...?

Answer 75

Whatever you do to one side, you must do to the other side.

Answer 76

Okay, so it would be 13 = x - 2 ?

Answer 77

You already forgot that taking a square root does not mean multiplying by 2...

Answer 78

... Okay.. So.. 3.25 = x-2

Answer 79

Taking a square root also does not mean dividing by 2. You already found the square root earlier...

Answer 80

.... Ok... 2.55...... so 2.55 = x - 2.....

Answer 81

And you also forgot that taking a square root leaves a plus or minus sign. \[\large \pm 2.55 = x - 2\]now solve for x you have to solve once for the + and once for the -), there will be two solutions.

Answer 82

Ok... so...

add two to both sides.. one for the plus..... so...

-2.55 = x... -2.55 + 2... = -0.55 = x....

Then 2.55 + 2 = 4.55 = x...

So -0.55, 4.55??

Answer 83

yes

Answer 84

Thanks.. So that's the final answer? -0.55,4.55?

Answer 85

Have to write as coordinates, those are the x's, the y's are both zero

Answer 86

So (-0.55,0),(4.55,0)..?

Answer 87

Yes

Answer 88

Thanks.