Question

Leo brought a bulldozer for 63103. The value of the bulldozer depreciated at a constant rate per year. The table below shows the value of the bulldozer after the first and second year.

Year 1
58054.74
Year 2
53410.38

Which function bets represents the value of the bulldozer after t years?

Answer 1

@Hero

Answer 2

F(t)=58054.76(0.92)^t
F(t)=63103(0.08)^t
F(t)= 63103(0.92)^t
F(t)=58054.76)(0.08)^t

Answer 3

You are given a function of the form \(y = ab^x\) where
a = the initial value of the bulldozer,
b = the constant rate of decrease
(x,y) = (t, F(t))

t is in years starting with t = 0.
F(t) = Value of the bulldozer after t years.

Answer 4

Yes

Answer 5

If you investigate the situation a bit further, you'll notice that you were given depreciation values for the first three years:

F(0) = 63103
F(1) = 58054.74
F(2) = 53410.38

Answer 6

Do you see this?

Answer 7

Yes

Answer 8

This means all you have to do is plug in the the values t = {0, 1, 2} in to the correct formula and you should receive the appropriate values for F(t).

Answer 9

One huge clue is this:

If F(0) = 63103, then 63103 must be the initial value of the function. Right?

Answer 10

I mean if that's the case, we at least know that

\(F(t) = (63103)b^t\)

Answer 11

It's c?

Answer 12

C is correct.