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what is the maximum value of xy when x+y =3
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xy=x(3-x)=3x-x^2 differentiating this will give 3-2x in maximum differentiation is zero 3-2x=0 x=1/2
and answer is ?
you know x, substitute it to x+y=3 and find y and then multiply x and y
thanks
(y)
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that idea word, except for the last step 3-2x=0 you get 3= 2x and x= 3/2 (not ½)
yes. sorry, my bad
Mathematica confirms phi's answer. Refer to the attachment where Maximize is a function from Mathematica's Constrainted Optimization function suite.
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