Question

log integrals

Answer 1

@AccessDenied

Answer 2

u=x+1
du = dx

Answer 3

\[\huge \int\limits \frac{ u }{ u-1 }du => \int\limits \frac{ 1 }{ u-1 }+1du\]

Answer 4

Did long division there.

Answer 5

\[\huge \int\limits\limits 1 du + \int\limits\limits \frac{ 1 }{ u-1 }du \]

Do another substitution here t = u-1, dt = du

\[\huge \int\limits \frac{ 1 }{ t }dt+\int\limits 1 du\]

Now integrate, and put in the limits.

Answer 6

im confused

Answer 7

you can also use the Fundamental Theorem, I think.