Prove the identity: (sin^2theta) x (csc^2theta) = sin^2theta +cos^2theta
First of all what is sin^2(x)+cos^2(x)=?
This is the most basic trig identity also know as a Pythagoras identity
And actually this identity has some restrictions
\[\sin^{2} \theta \csc ^{2} \theta=\sin^{2} \theta +\cos^{2} \theta\]
I honestly have no idea how to prove identities.. I;m sorry @freckles & @Homeworksucks
You should know sin^2(x)+cos^2(x)=1 and csc(x) =1/sin(x) Use these here
I don't really know anything, I'm new to this trig thing and my teacher is not helping at all. the way he explains it is too complicated
You can't get to an answer unless you make a good attempt. csc theta=1/sin theta Substitute that here and tell me what you get (sin^2theta) x (csc^2theta)
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