simplify the expression using the rules for exponents
(a^5b^-2c^-3)^4 / (a^-2b^-4c^5)^2

please help !

Question

simplify the expression using the rules for exponents
(a^5b^-2c^-3)^4 / (a^-2b^-4c^5)^2 

please help !

whpalmer4 · Answer

$$\frac{(a^5b^{-2}c^{-3})^4}{(a^{-2}b^{-4}c^5)^2}$$

I would start by using the property of exponents that $$(a^m)^n = a^{m*n}$$

What do you get after doing that?

anonymous · Answer

I honestly have no idea , I don't really get this -.-

whpalmer4 · Answer

go through the numerator.  take each letter with its exponent, and use the rule I gave you.  For starters: $(a^5)^4 = a^{5*4} = a^{20}$

whpalmer4 · Answer

next one up is $(b^{-2})^4 = $

a1234 · Answer

(a^5b^-2c^-3)^4 / (a^-2b^-4c^5)^2 

(a^5(1/b^2)(1/c^3)^4 / ((1/a^2)(1/b^4)(c^5))^2 

Can you simplify that further?

whpalmer4 · Answer

Come on, go through the steps.  $$(b^{-2})^4 = b^{-2*4} = $$What does  $-2*4=$?  That is the new exponent for $b$.  You're not allowed to say "idk" or "I don't get it" here.

anonymous · Answer

-8

whpalmer4 · Answer

Very good.  Now do the same for $$(c^{-3})^4 = $$

anonymous · Answer

okay so I understand you multiply the exponents , now I don't understand what to do after