Question

Help :(

Answer 1

whats ur question?

Answer 2

tell your question

Answer 3

What is the sum of a 6–term geometric series if the first term is 19 and the last term is 319,333?

372,552

392,160

411,768

431,376

Answer 4

hmmm sorry iv never done that

Answer 5

last term is the sixth term. You have to find 4 geometric means.
lets write that

\(\LARGE\color{blue}{ \bf t_1 \times r = t_2 }\)
\(\LARGE\color{blue}{ \bf t_1 \times r^{2} = t_3 }\)
\(\LARGE\color{blue}{ \bf t_1 \times r^{3} = t_3 }\) See why?

\(\LARGE\color{blue}{ \bf t_6 \div r^{ } = t_5 }\)
\(\LARGE\color{blue}{ \bf t_6 \div r^{2} = t_4 }\)
\(\LARGE\color{blue}{ \bf t_6 \div r^{3} = t_3 }\) See why?

I am demonstrating the relationship here...

So, if I say \(\LARGE\color{blue}{ \bf t_1 \times r^{3} = t_6 \div r^{3} }\)

then, can you solve for r?

(this won't be the final answer) (not yet...)

Answer 6

You know the t1 and t6, so you can do it.

Answer 7

Thank you. <3

Answer 8

Can you solve for the ratio for me please and show your work. If you want to farther work to make sure you leave with correct answer. I would prefer you to do this, but you don't have to if you don't want to.

Answer 9

So it will be 19 x r^3 = 319, 333/r^3

Answer 10

I made a mistake, sorry.