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OpenStudy (anonymous):
OpenStudy (anonymous):
sorry I don't know how to do this yet I would but sry...
OpenStudy (anonymous):
it's okay
OpenStudy (anonymous):
@ganeshie8 can you help her?
OpenStudy (anonymous):
@agent0smith
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OpenStudy (anonymous):
did you try bumping the question?
OpenStudy (anonymous):
yeah twice people just look at it for a while and leave
OpenStudy (anonymous):
same thing happens to me all the time
OpenStudy (anonymous):
what you can always do is reask the question
OpenStudy (anonymous):
Hmm yeah I guess but that just seems kind of pointless, yesterday when I was asking questions it took a lil over an hour for anyone to understand how to do it.
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OpenStudy (solomonzelman):
\[a^2+b^2=c^2\]
OpenStudy (anonymous):
when I did that I got 59.4
OpenStudy (agent0smith):
It makes a right triangle, since AB is tangent to the circle.
Use pythag as @SolomonZelman said.
OpenStudy (solomonzelman):
the missing side, is a leg, not a hypotenuse.
OpenStudy (anonymous):
ooo
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OpenStudy (solomonzelman):
\[b^2=c^2-a^2~~~~that gives,~~~b=±\sqrt{c^2-a^2}\]
in this case just + not -, b/c distance is always positive.
OpenStudy (anonymous):
thank you.
OpenStudy (solomonzelman):
\[b=\sqrt{(11.7)^2-(6)^2}\] Okay, just tell us what you get as the final ans. to make sure...
OpenStudy (anonymous):
10.0
OpenStudy (solomonzelman):
yes, good. I would approximate it to 10.04 (2 decimal places) but it's very good either way :)
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