Which integral expression can be used to find the area in the first quadrant bounded below by the x-axis and above by the curves y = sin x and y = cos x?

Question

anonymous · Answer

In the first quadrant, the graphs of sin(x) and cos(x) intersect at x = pi/4.

In that interval cos(x) has larger values than sin(x) so the integral will be for cos(x) - sin(x) and its limits will be x = 0 to x = pi/4
$$\int\limits_{0}^{\pi/4}\cos(x)-\sin(x)dx$$

anonymous · Answer

I am not sure which one it is.

anonymous · Answer

a = 0, b = pi/2... Upper limit is cos x and lower limit is sin x... Therefore...

$$\int\limits_{0}^{\pi/2} (\sin x - \cos x )dx$$

anonymous · Answer

Oh okay I misinterpreted it sorry!
The question is asking you about area above x-axis in the first quadrant bounded by sin and cos graphs.

The graph looks like this|dw:1400479744783:dw|