Question

12^(y-2)=20

Answer 1

12^(y-2)=20

hit both sides with log.

(y-2) log(12) = log(20)

y-2= log(20)/log(12)

y-2= log(base 12) 20

y=2+log(base 12) 20

Answer 2

Thanks @solomonZelman i was also wondering how to do that :)

Answer 3

Anytime :)

Answer 4

what do i do after the second step im lost

Answer 5

we are dividing both sides by log(12)

then we use the rule
\[\frac{\log(a)}{\log(c)}=\log_{~c}a\]

then add 2 to both sides

Answer 6

thanks