Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false.
\[4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + ... + 4n (4n+2) = \frac{ 4(4n+1) (8n+7) }{ 6 }\]
When I substitute n for 1 I don't get the same amount on both sides?
@precal @matricked
then what does that tell you about the proof?
hint: show why it doesnt work ...
Oh, so that's it? I just show that it doesn't work.
I'm sorry openstudy wouldn't load. I'm going to show you what I have written down and could you tell me if it's right or not?
thats all there is to it yes. its asking you to show it works, or show why it doesnt. since n=1 fails, then this doesnt work.
\[4(1)(4(1)+2) = 4(4(1)+1)(8(1)+7)\] 24 = 300 it doesn't equal so therefore it can't be be proven? or is it false or something?
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