Question

write f(x) = x^3 +4x^2+4x+16 as a product of linear factors
i think the answer is x =(x-4)(x+2)^

Answer 1

that not one of the answer choice in the question but i appreciate the help

Answer 2

what are the choices?

Answer 3

lol

Answer 4

A x =(x-4)(x+2)^2
B x= (X-4)(X-2)^2
c x =(x+4)(x-4)(x+)
d x=(x+4)(x+2i)(x-i)
e x= (x-4)^2(x-2i)

Answer 5

should be (x+4)(x+2i)(x-2i)

Answer 6

I prove
A) (x-4) (x+2)^2 = (x-4)(x^2+4x+4) = x^3 +4x^2+4x-4x^2-16x-16= x^3-12x-16
not the original problem, reject
B)(x-4)(x-2)^2= (x-4)(x^2-4x+4) = x^3 -4x^2+4x-4x^2+16x-16= x^3-8x^2+20x-16
not the original problem, reject
C) (x+4)(x-4)(x+? ) no matter what the last one is, it 's still wrong. because the first 2 terms give you x^2 -16 and the last term of the original one is +16, not -16, done
D) (x+4) (x+2i)(x-i) never be a correct answer, because for the imaginary root, it is always a pair of it, it is never be 2i and i
E) (x-4)^2(x-2i) the same logic with the above

Answer 7

thank you both for the answer and explaining it

Answer 8

even though the option D is (x+4)(x+2i)(x-2i) = (x+4) (x^2-(2i)^2) = (x+4) (x^2 -4) = x^3-4x+4x^2 -16
reject still.

Answer 9

so, I shouldn't sue the calculator company, right? hahahaa

Answer 10

You don't have the correct options or YOU POST THE WRONG PROBLEM hehehe

Answer 11

im going with C it has to be right

Answer 12

it's up to you

Answer 13

I think option d should have a -2i in the last bracketed term
(X+4)(X+2i)(x-2i) = (x+4)(x^2+4)